socket formulae variations and odds
#5
adeyke,Oct 6 2004, 04:39 PM Wrote:Okay, I'll rephrase:
Mathematically, if an item has a maximum of n sockets, the chance of getting n is (7 - n)/6, the chance of getting any specific number > n sockets is 0, and the chance of getting any specific number < n sockets is 1/6.
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Gotcha, I missed that the first time I read the reply :blink:

5=max

7-5 = 2

2/6 = odds at max
1/6 = 4, 3, 2, 1
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Messages In This Thread
socket formulae variations and odds - by adeyke - 10-06-2004, 03:25 PM
socket formulae variations and odds - by adeyke - 10-06-2004, 04:39 PM
socket formulae variations and odds - by gta-maloy] - 10-06-2004, 04:43 PM
socket formulae variations and odds - by dta - 11-20-2004, 01:14 PM
socket formulae variations and odds - by adeyke - 11-20-2004, 04:08 PM

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