Math Question

[kandrathe]

I think you got there.

I'm pretty sure that's the answer, but I'm curious to Lissa's post. Perhaps its a more accurate number than mine, however from what I've seen of the formula in use, the outcome was not as I expected.

If I understand the problem...

In your example of two dice, one die must = 10 in order to consider the second die, so it is always 1 in 10 or 10%, and you would multiply that times the probability of the second die.

.1 x .1 = ten & ten = .01 or 1 in 100 or 1%
.1 x .2 = ten & (10 or 9) 2 ways of ten = .02 or 2 in 100 or 2%
...
.1 x .9 = ten & (10, 9, 8, 7, 6, 5, 4, 3, or 2) = .09 or 9%
.1 x 1 = ten & (any) 1 in 10 or 10%