Climate Policy

[Zenda]

Nope. I think the 150W/m2 is the results of measuring the suns angle and the number of cloudy days.

You think so? Should you not be sure, before using that number as a basis for your calculations? Anyway, like I said, you can assume winter conditions all year long, and multiply the costs with 3 to arrive at $31.50 per month.

Btw, I'm not claiming that $10 to $30 per month is realistic. It just the result of your faulty assumptions and wrong approach.

Do you use 2520 / $3 = 840 watts in a day?

Don't you have any feeling for numbers?

Allright, let's calculate backwards. One Watt is 1 Joule/Second, and 1 Wh is 3600 Joule. If you need 20 kWh per day, you need 20*3600*1000 = 72.000.000 joules per day. If $3 gives you 1 joule/second for 8 hours a day (your winter conditions), it would yield 1*8*3600 = 28.800 Joules per day. So, you would need 72000000/28800 = 2500 units of $3, which is $7500. Which is 3 times the $2500 we had earlier, like I predicted.

Here is an description of one persons journey with installing solar power. His bids ranged from $38K to $60K after rebate(s).

Well, I guess that shows you are wrong too. This person has the following conclusion:

http://www.extremetech.com/article2/0,28...685,00.asp

"So our estimated annual power bill will drop from about $4,400 a year to less than $1,100 a year, with the average cost per kWH dropping from 25 cents to 6.3 cents. The payback time, assuming energy costs don't spike steeply, is a little under nine years."