Math problem : Reloaded!
#15
The answer is simple, well atleast to me it seems so.

Since you have two jars. You pick one at random and you pick a ball at random (blindfolded?). Therefore, 25 white balls and 25 black ones in each jar.

If you pick either jar, you will have equal chance of picking a white ball as a black ball. Thus you have a 50% chance of winning all the time. If you chance the distribution around then the chance's of winning increase, for a certain jar but decrease for the other. Thus the best way is to keep it even.
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Messages In This Thread
Math problem : Reloaded! - by rashban - 06-06-2003, 12:51 AM
Math problem : Reloaded! - by Xaeshan - 06-06-2003, 12:57 AM
Math problem : Reloaded! - by [wcip]Angel - 06-06-2003, 01:00 AM
Math problem : Reloaded! - by the Langolier - 06-06-2003, 03:46 AM
Math problem : Reloaded! - by whyBish - 06-06-2003, 06:29 AM
Math problem : Reloaded! - by Thecla - 06-06-2003, 06:30 AM
Math problem : Reloaded! - by Drasca - 06-06-2003, 11:36 AM
Math problem : Reloaded! - by ithil - 06-06-2003, 12:13 PM
Math problem : Reloaded! - by Occhidiangela - 06-06-2003, 02:40 PM
Math problem : Reloaded! - by --Pete - 06-06-2003, 03:31 PM
Math problem : Reloaded! - by --Pete - 06-06-2003, 03:52 PM
Math problem : Reloaded! - by --Pete - 06-06-2003, 03:55 PM
Math problem : Reloaded! - by CowInvader - 06-07-2003, 01:38 AM
Math problem : Reloaded! - by Drasca - 06-07-2003, 06:33 AM
Math problem : Reloaded! - by DralaFi - 06-11-2003, 01:54 AM
Math problem : Reloaded! - by --Pete - 06-11-2003, 02:09 AM
Math problem : Reloaded! - by gekko - 06-11-2003, 02:10 AM
Math problem : Reloaded! - by --Pete - 06-11-2003, 02:17 AM

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